factorise 6ab-b square+12ac-2bc
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= 6ab + 12ac -b^2 -2bc
= (6ab + 12ac) - (b^2 + 2bc)
= 6a (b +2c) - b(b+ 2c)
=(6a - b) (b+ 2c)
= (6ab + 12ac) - (b^2 + 2bc)
= 6a (b +2c) - b(b+ 2c)
=(6a - b) (b+ 2c)
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