Question

factorise 6x^2+17x+5 by factor theorem

Answer 1

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Answer 2

By factorising, the value of x for the given term is $\frac{-1}{3}$, $\frac{-5}{2}$.

Step-by-step explanation:

Given:

Factorise $6x^2$+17x+5 by factor theorem

Solution:

To obtain the factors of the given expression using factor theorem,

$6x^2$ + 17x+5 can be written as $6x^2$+ 15x+ 2x + 5

= 3x (2x + 5) + 1 (2x + 5)

= (3x + 1) (2x + 5)

3x + 1= 0,

x = $\frac{-1}{3}$.

2x + 5 = 0,

x = $\frac{-5}{2}$.

The value of x for the given term is $\frac{-1}{3}$, $\frac{-5}{2}$.

To know more:

Factorise 6 X square + 17 X + 5 by splitting the middle term and by using the factor theorem

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