Math, asked by charkhiyash, 7 months ago

factorise: 6x^2+7x-3
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Answers

Answered by aditya926876
1

Answer:

6x^2+7x^2-3

6x^2+9x-2x-3

3x(2x+3)-1(2x+3)

(3x-1)(2x+3)

so values of x are

x= 1/3 , x= -3/2

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Answered by MissKalliste
7

Answer:

\bullet\large\textsf{(2x+3)(3x-1)}

Step-by-step explanation:

\mapsto6x^2 + 7x - 3

\mapsto6x^2 - 2x+9x-3

As we know, the coefficient of first term should be 1, so we have to multiply it with the last term : 6 × 3 = 18 (Therefore, we can get the factors of 18)

\mapsto2x (3x-1) + 3 (3x-1)

\bold\mapsto(2x + 3) (3x-1)

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