Factorise 6x^3+10x^2+8
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Substituting, 0,1 etc, it is clear that 0 is not a factor. 1 is a factor. So x-1 is one factor.
Dividing the given polynomial by x-1, 6x^2 +16x + 8 is the binomial. Looking at this, the product of roots is 48 and Sum is 16. So using 12 and 4, we get
6x^2 + 12x + 4x +8 which is
6x(x+2)+ 4(x+2) which is
(x+2)(6x+4).
Thus we get the 3 factors, (x-1), (x+2) and (6x+4).
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