Question

factorise 6x^5-22x^3-8x​

Answer 1

Answer:

${6}^{2} - {22x}^{3} - 8x = 0\\ 2x( {3x}^{4} - {11x}^{2} - 4) = 0\\ {3x}^{4} - {12x}^{2} + {x}^{2} - 4 = 0 \\ {3x}^{2} ( {x}^{2} - 4) = 0 \\ ( {3x}^{2} + 1)( {x}^{2} - 4) = 0$

which is the required fatorisation