Question

factorise 6x cube + 5x square -12x +4​

Answer 1

Answer:

Step-by-step explanation:

Solution :-

checking x = 1,2, _____ we get,

At x = 1 :-

→ 6x^3-5x^2-17x+6

→ 6*(0)³ - 5*(0)² - 17*0 + 6

→ 0 - 0 - 0 + 6

→ 6 = Not Possible .

At x = 2 :-

→ 6x^3-5x^2-17x+6

→ 6*(2)³ - 5*(2)² - 17*2 + 6

→ 6*8 - 5*4 - 34 + 6

→ 48 - 20 - 28

→ 48 - 48

→ 0.

Hence, we can say That, (x - 2) will be Factor of Given Polynomial . . (As Remainder is 0).

So, Dividing The Polynomial by (x - 2) now, we get,

x - 2 ) 6x³ - 5x² - 17x + 6 ( 6x² + 7x - 3

6x³ - 12x²

7x² - 17x

7x² - 14x

-3x + 6

-3x + 6

0

Factorising The Quotient Now :-

→ 6x² + 7x - 3

→ 6x² + 9x - 2x - 3

→ 3x(2x + 3) - 1(2x + 3)

→ (2x + 3)(3x - 1)

Hence, Factors of cubic Polynomial 6x^3-5x^2-17x+6 is (x-2)(2x+3)(3x - 1).

Answer 2

Step-by-step explanation:

6x^3 because it is a cubic formula