Factorise 6x2 +17x+5
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Answered by
0
Here is the answer
ANSWER
Let p(x)=6x
2
+17x+5 the term
6
5
can be written as many terms one would be (±
2
5
,±
3
1
),(±
6
5
,±1),...……....
Let p(
3
−1
)=0 then by factor theorem
3
−1
then the other will be;
6x
2
+17x+5=(2x+5)(3x+1)
Answered by
9
Answer :-
6x^2 + 17x + 5
By middle term splitting,
According to that we need to find two numbers, p and q whose sum is 17 and product is 30 .
- So if we take numbers 6 and 5
so 6 + 5 = 11 and 6 * 5 = 30
The sum of 6 and 5 is not equals to 17 .
- Now, we take numbers 3 and 10
So, 3 + 10 = 13 and 3 * 10 = 30
The sum of 3 and 10 is not equals to 17.
- Now, we take numbers 2 and 15
So, 2 + 15 = 17 and 2 * 15 = 30
It satisfies the method of middle term splitting as its sum is equal to 17 and product is equals to 30 .
6x^2 + 2x + 15x + 5
2x( 3x + 1 ) + 5( 3x + 1 )
(2x + 5 ) ( 3x + 1 )
( 2x + 5) ( 3x + 1 ) is your answer mate
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