Question

factorise 6x²-18x +12​

Answer 1

=> 6x² -18x +12

=> 6x² -12x -6x + 12

=> 6x(x-2) -6(x-2)

=> (x-2)(6x-6)

Answer 2

Given

$6 {x}^{2} - 18x + 12 = 0$

We need factorise the above quadratic

equation

$6 {x}^{2} - 18x + 12 = 0$

splitting the middle term

$6 {x}^{2} - 6x - 12x + 12 = 0$

$6x(x - 1) - 12(x - 1) = 0$

$(6x - 12)( x - 1) = 0$

$(1).(6x - 12) = 0$

$6x = 12$

$\boxed{ x = 2}$

$(2).(x - 1) = 0$

$\boxed{x = 1}$

what is a quadratic equation?

◼A quadratic is equation is an equation of degree 2 and have the form ax^2+bc+c=0

◼This equation may have real roots or imaginary roots

◼Here a,b,c are constants