Question

factorise 6x³-5x²-13x+12​

Answer 1

Answer:

(x-1)(2x+3)(3x-4)

I hope it is a right answer

Answer 2

Consider the given that 6x3−5x2−13x+12

Put x=1 and we get,

  6(1)3−5(1)2−13(1)+12

 =6−5−13+12=0

Then, x=1 and x−1=0 is a factor.

Now figure above

  6x3−5x2−13x+12=(x−1)(6x2+x−12)=0

 ⇒(x−1)(6x2+x−12)=0

 ⇒(x−1)(6x2+(9−8)x−12)=0

 ⇒(x−1)(6x2+9x−8x−12)=0

 ⇒(x−1)[3x(2x+3)−4(2x+3)]=0

 ⇒(x−1)(3x−4)(2x+3)=0

If x−1=0 then x=1

If 3x−4=0  then  x=4/3

If 2x+3=0  then  x= -3/2

Hence, the factor is 1,−3/2 and 4/3.