Question

Factorise : 6x³– 5x²– 13x + 12
Pls also help with this one! I am not able to solve this.... Pls anybody help!!!!

Answer 1

Answer:

x=1,4/3,-3/2

by synthetic division method

Answer 2

Answer:

Step-by-step explanation:

6x³– 5x²– 13x + 12

add all coefficients

⇒ 6 - 5 - 13 + 12 = 18 - 18 = 0

here, in this case, sum of coefficients = 0

⇒ root of the equation is 1

⇒ x = 1

⇒ (x - 1) = 0

now divide 6x³– 5x²– 13x + 12 with (x - 1)

⇒

x - 1) 6x³– 5x²– 13x + 12 (6x² + x - 1

  (-)  6x³ - 6x²                

                 x² - 13x

       (-)       x² - x            

                      -12x + 12

       (-)           -12x + 12  

                           0        

⇒  6x³– 5x²– 13x + 12 = (x - 1)(6x² + x - 1)

                                    = (x - 1)(6x² + 3x - 2x - 1)

                                    = (x - 1)[3x(2x + 1) -1(2x + 1)]

6x³– 5x²– 13x + 12 = (x - 1)(3x-1)(2x+1)

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