Question

Factorise:

6x³ + x² -10x +3
Plz it's urgent

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Answer 1

$\huge\mathfrak\green{\bold{\underline{☘{ ℘ɧεŋσɱεŋศɭ}☘}}}$

$\red{\bold{\underline{\underline{❥Question᎓}}}}$Factorise:

6x³ + x² -10x +3

$\huge\tt\underline\blue{❯Answer❮</p><p> }$

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$6 {x}^{3} + {x}^{2} - 10x + 3$

put x=1 to check

$6 {(1)}^{3} + {(1)}^{2} - 10 + 3$

$7 - 10 + 3$

$- 3 + 3 = 0$

therefore,(X-1 ) is a factor of the given polynomial

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нσρє ıт нєłρs yσυ

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тнαηkyσυ

Answer 2

ANSWER✔

$\large\underline\bold{GIVEN,}$

$\dashrightarrow p(x)= 6^3+x^2-10x+3$

$\large\underline\bold{TO\:FIND,}$

$\dashrightarrow to\: factorise\:the\:given\:p(x)$

$\large\underline\bold{SOLUTION,}$

$\dashrightarrow Let\:us\:take\:g(x)\:as\:(x-1)$

$\therefore dividing\:p(x)\:by\:g(x)\\ We\:get,$

$\red{\text{FOR\: THESE PROCESS REFER THE ATTACHMENT,}}$

$\dashrightarrow Answer\:we\:get\:is\:(x-1)[6x^2+7x-3]$

$\therefore factorising\:the\: remaining\:$

$\dashrightarrow (x-1)[6x^2+7x-3]$

$\implies (x-1)[6x^2+9x-2x-3]$

$\implies (x-1)[ 3x(2x+3)-1(2x+3)]$

$\implies (x-1)(3x-1)(2x+3)$

$\large{\boxed{\bf{ \star\:\:(x-1)(3x-1)(2x+3) \:\: \star}}}$

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