Math, asked by devpriyaksreejesh123, 1 month ago

Factorise: 6xy(a^2+b^2)+8yz(a^2+b^2)-10xz(a^2+b^2)​

Answers

Answered by nagakamalagrandhi
0

Answer:

6xy(a2 + b2) + 8yz(a2 + b2) - 10xz(a2 + b2)

H.C.F. of 6, 8, 10 = 2,

then 2(a2 + b2) (3xy + 4yz - 5xz)

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Answered by RosyCherry
1

Answer:

2(a^2+b^2) (3xy+4yz-5xz)

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