Question

factorise 6xy+x^2+9y^2-4a^2​

Answer 1

Answer:

(x+3y+4a)(x+3y-4a)

Step-by-step explanation:

$6xy + {x}^{2} + 9 {y}^{2} - 4 {a}^{2} \\ = {x}^{2} + 6xy + 9 {y}^{2} - 4 {a}^{2} \\ = {x}^{2} + (3 + 3)xy + 9 {y}^{2} - 4 {a}^{2} \\ = {x}^{2} + 3xy + 3xy + 9 {y}^{2} - 4 {a}^{2} \\ = x(x + 3y) + 3y(x + 3y) - 4 {a}^{2} \\ = (x + 3y)(x + 3y) - 4 {a}^{2} \\ = {(x + 3y)}^{2} - 4 {a}^{2} \\ = (x + 3y + 4a)(x + 3y - 4a)$

Answer 2

Step-by-step explanation:

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