Question

factorise:6ysquare+11y-7

Answer 1

Answer :

$given \: expression \: = {6y}^{2} + 11y - 7 \\ \\ firstly \: write \: 11y \: as \: difference \: \\ \\ = > \: {6y}^{2} + 14y - 3y - 7 \\ \\ = > \: factor \: out \: 2y \: from \: the \: expression \: \\ \\ = > \: 2y(3y + 7) - 3y - 7 \\ \\ = > \: extract \: the \: negative \: sign \: from \: the \: expression \: - 3y - 7 \\ \\ = > \: 2y(3y + 7) - (3y + 7) \\ \\ = > \: factor \: out \: 3y + 7 \: from \: the \: expression \\ \\ = > \: (3y + 7)(2y - 1)$



Hope it would help you

Answer 2

6y²+14y-3y-7=0

2y(3y+7)-1(3y+7)=0

(3y+7)(2y-1)=0

y=-7/3 , y=1/2