Math, asked by shinchan48, 1 year ago

factorise:6ysquare+11y-7

Answers

Answered by Anonymous

Answer :

$given \: expression \: = {6y}^{2} + 11y - 7 \\ \\ firstly \: write \: 11y \: as \: difference \: \\ \\ = > \: {6y}^{2} + 14y - 3y - 7 \\ \\ = > \: factor \: out \: 2y \: from \: the \: expression \: \\ \\ = > \: 2y(3y + 7) - 3y - 7 \\ \\ = > \: extract \: the \: negative \: sign \: from \: the \: expression \: - 3y - 7 \\ \\ = > \: 2y(3y + 7) - (3y + 7) \\ \\ = > \: factor \: out \: 3y + 7 \: from \: the \: expression \\ \\ = > \: (3y + 7)(2y - 1)$

Hope it would help you

shinchan48: can u answer my second question please

Anonymous: I was to answer but your Question had been deleted

shinchan48: i again posetd it

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Answered by tusharsinsinwar123

6y²+14y-3y-7=0

2y(3y+7)-1(3y+7)=0

(3y+7)(2y-1)=0

y=-7/3 , y=1/2

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