factorise : 7(3a - b)² - 28(2a - b)²
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Answers
Answer:
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Step-by-step explanation:
Given:−
\text {➺7} {(3a-b)}^2 {-28} {(2a-b)}^2➺7(3a−b)
2
−28(2a−b)
2
\text {➺(21a-7b)}^2 {-(56a-28b)}^2➺(21a-7b)
2
−(56a−28b)
2
\sf {\underline {\mathtt {\red {➻Using\: formula:- }}}}
➻Usingformula:−
\boxed {{➺a}^2 -{b}^2 {=(a+b) (a-b)}}
➺a
2
−b
2
=(a+b)(a−b)
\sf {\underline {\mathtt {\orange {➻Where\: , }}}}
➻Where,
\text {➺a=(21a-7b)}➺a=(21a-7b)
\text {➺b=(56a-28b)}➺b=(56a-28b)
\sf {\underline {\mathtt {\pink {➻Applying\: formula:- }}}}
➻Applyingformula:−
\text {➺(21a-7b+56a-28b) (21a-7b-(56a-28b))}➺(21a-7b+56a-28b) (21a-7b-(56a-28b))
\text {➺(77a-35b) (21a-7b-56a+28b)}➺(77a-35b) (21a-7b-56a+28b)
\text {➺(77a-35b) (-35a+21b)}➺(77a-35b) (-35a+21b)
\sf {\boxed {\underline {\mathtt {\purple {➻Hence\: Simplified }}}}}
➻HenceSimplified
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\sf {\mathtt {\blue {!
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Answer:
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Step-by-step explanation:
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