Factorise: 7(3x--4y)²--28(2x--y)²
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Answer:
7(3x-4y)² - 28(2x-y)²
= 7[9x²+16y²-24xy - 4(4x²+y²-4xy)]
= 7[9x²+16y²-24xy-16x²-4y²+16xy]
= 7(-7x²+12y²-8xy)
= -49x²+84y²-56xy
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