Question

Factorise: 7 (a + 2b)² – 21 (a + 2b)
using Factorisation by Regrouping terms​

Answer 1

Answer:

answer for the given problem is given

Answer 2

$7(a+2b)^{2} - 21(a+2b)$

$= 7(a+2b)(a+2b) - 3 \times 7(a+2b)$

$= 7(a+2b)(a+2b - 3 )$

Therefore.,

$\red{ Factors \:of \:7(a+2b)^{2} - 21(a+2b)}$

$\green{ = 7(a+2b)( a+2b - 3 )}$

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