Question

Factorise: 7(x – 2y)2 – 25(x -2y) + 12

Answer 1

Answer:

Step-by-step explanation:

Let x - 2y =P

=7P2- 25P + 12

Splitting middle term

= 7p2 - 21p - 4p + 12

= 7p ( p -3 ) - 4 (p - 3)

=( p -3 )(7p - 4 )

Substituting p = x -2 y

= ( x - 2y - 3 ) { 7 ( x - 2y ) - 4 }

= ( x - 2y - 3 ) ( 7x -14y - 4 )

I.e. = 7 ( x - 2y ) ^2 - 25 ( x - 2y ) + 12 = ( x - 2y - 3 ) ( 7x - 14 y - 4)

No common factor so can't be factorised

Answer 2

Question:

Factorise: $7(x-2y)^2-25(x-2y)+12$

Answer:

Hence this equation does not has any common factor.

Step-by-step explanation:

The Given equation is

⇒$7(x-2y)^2-25(x-2y)+12$

We can see that $(x-2y)^2$ is in the form of $(a+b)^2=a^2+2ab+b^2$

⇒$[7*{(2x-y)^2}] - 25*(x-2y) + 12$

⇒${7(4x^2 - 4xy +y^2)} - 25x + 50y + 12$

⇒$28x^2 - 28xy + 7y^2 - 25x +50y +12$

⇒$28x^2 - 28xy - 25x + 7y^2 + 50y +12$

We can see that there is common factor

Hence this equation does not has any common factor.