factorise 729x^3 - 512y^3
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Answer:
⟼ 729x³−512y³
⟼=9³x³−8³y³
⟼=(9x)³−(8y)³
⟼=(9x−8y)[(9x)²+(8y)²+(9x)×(8y)]
⟼=(9x−8y)(81x²+64y²+72xy)
⟼=(9x−8y)(81x²+64y²+72xy
(a³−b³)=(a−b)(a²+b²+ab).
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