Question

factorise 7ab²c+21a²bc²-35abc pls tell step by step full solution​

Answer 1

Step-by-step explanation:

here , all the numbers can be divided by 7.

so , by taking 7 common in this equation we get ,

7 ( ab²c + 3a²bc² - 5abc)

now a , b and c is also common in all terms.

so we can also take abc as common .

7abc ( b + 3ac - 5)

so , hence

7abc ( b + 3ac - 5) is the factor