Question

factorise 7x^2-19x-6

Answer 1

Following are the steps for getting the answer:

Given:

$7x^2-19x-6$

To find:

Factor of $7x^2-19x-6$

Solution:

we have to factorize the $7x^2-19x-6$

so,

$7x^2-19x-6$

we can write this expression

7x²-21x+2x-6

as(-21x+2=-19x)

we will take the common 7x from the 7x²-21x and 2 from2x-6

we get,

7x(x-3)+2(x-3)

we will write it like

=(x-3)(7x+2)

Thus, the factor of $7x^2-19x-6$ is (x-3)(7x+2)

Answer 2

Given,

Factorize $7x^{2}-19x-6$

Here, we have to use the factorization splitting method

We split the middle term in the quadric as $px+qx$ and get desired  factors by grouping the terms.

So, First we have to split the middle term

$7x^{2} -19x-6=0$

Here, we have to written $- 19x=-21x+2x$

$7x^{2} -21x+2x-6=0$

Lets, take $7x$ common from $7x^{2} -21x$

$7x(x-3)+2x-6$

Take $2$ common from $2x-6$

$7x(x-3)+2(x-3)$

From the above equation,

$(x-3)(7x+2)=0$

Therefore, the factors of $7x^{2}-19x-6$ is $(x-3)(7x+2)$.