Question

Factorise -7x+3+4x^3​

Answer 1

Answer:req factors are  ( x-1)  $(x-\frac{1}{2} ) and (x+\frac{3}{2} )$

Step-by-step explanation:

the givn eqn. is $4x^{3} -7x +3$.

by hit and trial method if we divide this eqn by (x-1) it leaves remainder 0.

This shows tha (x-1) is a factor of given eqn.

Now, for other factors.

We have,

$4x^{3} -7x +3\\=(x-1) (4x^{2} + 4x-3)$

Now for $(4x^{2} + 4x-3)$ ,using quadratic formula

we will have

$x= \frac{1}{2} \\also \\\\x= - \frac{3}{2}$

thus other two factors are $(x-\frac{1}{2} ) and (x+\frac{3}{2} )$