Question

Factorise 7y^2-8y+3​

Answer 1

Answer :

(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)

$\underline{\underline{{\purple{\sf Given}}}}$

$\longrightarrow\displaystyle\small\boxed{\tt\red{7y^2-8y+3}}$

$\implies \small \boxed{ \tt \blue{by \: formula \: method}}$

$\implies \displaystyle \sf{x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} }$

$\implies \displaystyle \sf{x = \frac{8 \pm \sqrt{ {8}^{2} - 4(7)(3) } }{2 \times 7} }$

$\implies \displaystyle \sf{x = \frac{8 \pm \sqrt{64 - 24\times 3} }{14} }$

$\implies \displaystyle \sf{x = \frac{8 \pm \sqrt{64 - 84} }{14} }$

$\implies \displaystyle \sf{x = \frac{8 \pm \sqrt{ - 20} }{14} }$

$\implies \displaystyle \sf {x = \frac{8 \pm 2\sqrt{5} }{14} }$

$\implies \displaystyle \sf{x = \frac{2(4 \pm \sqrt{5} )}{2 \times 14} }$

$\implies \displaystyle \sf {x = \cancel\frac{2}{2} \frac{4 \pm \sqrt{5} }{7} }$

$\implies \displaystyle \sf{x = \frac{4 + \sqrt{5} }{7} and \: x = \frac{4 - \sqrt{5} }{7} }$

$\mapsto \displaystyle \small \boxed{ \sf \red{ \: the \: roots \: are \: x = \frac{4 + \sqrt{5} }{7} \: and \: x = \frac{4 - \sqrt{5} }{7} }}$