factorise:
8 (2 X + Y) square + 8 x + 4 Y
(With Explanation)
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GIVEn
8(2x + y)² + 8x + 4y
Factories it
SOLUTIOn
→ 8(2x + y)² + 8x + 4y
→ 8(2x + y)² + 4(2x + y)
Take (2x + y) as a common
→ 4(2x + y)[2(2x + y) + 1]
→ 4(2x + y)[4x + 2y + 1]
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