Math, asked by truck, 1 year ago

factorise 8 ( 2x -3y ) square - 10 (2x -3y )

Answers

Answered by garylaupapvsl

$8(2x -3y)^2-10(2x -3y)$
= $2(2x-3y)(4(2x-3y)-5)$ (Factor out 2(2x-3y))
= $2(2x-3y)(8x-12y-5)$ (Expand 4(2x-3y))

truck: Please explain this factorise i can understand

garylaupapvsl: 8(2x-3y)^2-10(2x-3y) what we can do firstly is take out common factor, that is 2(2x-3y)

so the next operation will be 2(2x-3y) times something

and now we factor the original equation with 2(2x-3y)

(I'll do it step by step)
8(2x-3y)^2 divide by 2(2x-3y)
=8(2x-3y)(2x-3y) divide by 2(2x-3)
=4(2x-3y)

-10(2x-3y) divide by 2(2x-3y)
=-5

garylaupapvsl: Combine both of them = 4(2x-3y)-5

so 8(2x-3y)^2-10(2x-3y) = 2(2x-3y)(4(2x-3y)-5)

and the next step we can do is expand the 4(2x-3y)-5 to simplify it.

4(2x-3y)-5=8x-12y-5

The final answer is 2(2x-3y)(5=8x-12y-5).

Hope this can help you :)

truck: thanks

truck: For helping me in understanding

garylaupapvsl: You're welcome :)

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