Question

factorise 8-50y^2z^ 2

Answer 1

Answer:

@.2.47 (b)7.095 = -4/9 + 38/13 = (-4)×13/9 + 9x(38)/13 = -52/9। + 342/13 = -52+342/117 = 290/117 %3D = (2.47)

Answer 2

Given expression:

$8-50y^{2} z^{2}$

$=(2\times4)-(2\times25) y^{2} z^{2}$

Here, $4$ and $25$ are perfect squares.

So, let us take '$2$' common from the above expression.

$=2(4-25y^{2} z^{2} )$

Here, $4$ can be written as '$2^{2}$' and $25y^{2} z^{2}$ can be written as '$(5yz)^{2}$'.

$=2[(2)^{2} -(5yz)^{2} ]$

We know that, $a^{2} -b^{2} =(a+b)(a-b)$.

Here, $a=2$ and $b=5yz$.

$=2[(2+5yz)(2-5yz)]$.

Hence, $2(2+5yz)(2-5yz)$ is the factorized form of the given expression.