factorise 8 a cube minus b cube minus 64 C cube minus 24 ABC
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Answer:
(2a)³-(b)³-(4c)³-3(2a)(b)(4c)= (2a-b-4a)((2a)²+(b)²+(4c)²-(2a)(-b)-(-4c)(-b)-(-4c)(2a
Step-by-step explanation:
=> x³+y³+z³-3xyz=(x+y+z)(x²+y²+z²-xy-yz-zx)
(2a)³-(b)³-(4c)³-3(2a)(b)(4c)= (2a-b-4a)((2a)²+(b)²+(4c)²-(2a)(-b)-(-4c)(-b)-(-4c)(2a)
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