Question

factorise 8 cube - (2x-y)the whole cube​

Answer 1

Answer:

${\huge{\underline{\underline{\mathfrak{\pink{HOLA}}}}}}$

$<font color="red">$

8x^3-(2x-y)^3

=(2x)^3-(2x-y)^3

=[2x-(2x-y)][(2x)^2-2x*(2x-y)+(2x-y)^2]

=[2x-2x-y][4x^2-4x^2+2xy+4x^2-4xy+y^2]

=(-y)[4x^2-2xy+y^2]

Answer 2

Answer:

The answer is explained in the image.