Question

Factorise 8(p – 2q )2 – 2p + 4q – 1

Answer 1

Answer:

16(p-2q)-2(p-2q)-1

(p-2q)[(16-2)-1]

(p-2q)(13)

Answer 2

✪AnSwEr

${\tt{\red{\underline{\large{Given}}}}}$

• Factorize
• 8(p – 2q )² – 2p + 4q – 1

${\sf{\green{\underline{\large{To\:find}}}}}$

• Factor of this polynomial

${\sf{\pink{\underline{\Large{Explanation}}}}}$

• First of visualise the like terms
• get the terms which are common
• By doing commonig (+,-)
• Try to do in steps

8(p – 2q )² – 2p + 4q – 1

=>8(p – 2q )²– (2p - 4q) – 1

=>(p – 2q )² –2 (p - 2q) – 1

• Getting (p - 2q) as common

=>(p – 2q )² –2 (p - 2q) – 1

=>(p-2q) (p-2q-2-1)

=>(p-2q) (p-2q-3)

Hence factorize