Question

factorise 8 P cube - 125q cube

Answer 1

$8 {p}^{3} - 125 {q}^{3} \\ using \: {a}^{3} - {b}^{3} = (a - b)( {a}^{2} + {b}^{2} + ab) \\ {(2p)}^{3} - {(5q)}^{3} = (2p - 5q)(4 {p}^{2} + 25 {q}^{2} + 10pq)$

Answer 2

hay!!

Dear friend -

here is ur answer

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8p³-125q³

=> (2p) ³-(5q)³

=> now, we used that formula a³-b³

=> (2p-5q) { (2p)² +2p×5q + (5q) ²}

=> (2p-5q) (4p²+10pq+25q²)

I hope it's help you