Question

factorise : 8/x^3-27x^3​

Answer 1

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We know the identity a3−b3=(a−b)(a2+b2+ab)

Using the above identity, the equation 8x3−27y3 can be factorised as follows:

8x3−27y3=(2x)3−(3y)3=(2x−3y)[(2x)2+(3y)2+(2x×3y)]=(2x−3y)(4x2+9y2+6xy)    

Hence, 8x3−27y3=(2x−3y)(4x2+9y2+6xy) 

Step-by-step explanation:

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