Math, asked by mariyaattar110, 11 months ago

factorise: 8 (x-3y)^2+4 (x-3y)​

Answers

Answered by Anonymous
3

\huge\boxed{\fcolorbox{cyan}{grey}{Solution:-}}.

Factorise of :- 8(x-3y)²+4(x-3y)

8(x-3y)²+4(x-3y)

= (x-3y)[ 8(x-3y)+4]

= (x-3y)(8x-24y+4)

\huge\boxed{\fcolorbox{cyan}{grey}</em></strong><strong><em>{</em></strong><strong><em>H</em></strong><strong><em>o</em></strong><strong><em>p</em></strong><strong><em>e</em></strong><strong><em>s</em></strong><strong><em> </em></strong><strong><em>i</em></strong><strong><em>t</em></strong><strong><em>s</em></strong><strong><em> </em></strong><strong><em>h</em></strong><strong><em>e</em></strong><strong><em>l</em></strong><strong><em>p</em></strong><strong><em>s</em></strong><strong><em> </em></strong><strong><em>u</em></strong><strong><em>:-}}

Answered by alfasingh007
14

Answer:

8(x-3y)^2+4(x-3y)

let x-3y=z.........(1)

8z^2+4z

=4z(2z+1)

on putting the value of z...

=4(x-3y)(2x-6y+1)

Similar questions