Factorise: 8(x-3y)^2 +4(x- 3y)
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Answer:
4(x-3y)[2(x-3y)+1]
Step-by-step explanation:
let(x-3y)be z
therefore,
8z^2+4z
=4z(2z+1)
substituting the value
4(x-3y)[2(x-3y)+1]
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