factorise 8(x-3y)^2+4(x-3y)....
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Answers
Answered by
0
Step-by-step explanation:
4(2x−3y)
2
−8x+12y−3
=4(2x−3y)
2
−4(2x−3y)−3
Let (2x−3y) be a
Therefore,
=4a
2
−4a−3
=4a
2
−6a+2a−3
=2a(2a−3)+1(2a−3)
=(2a+1)(2a−3)
Putting the value of a we get,
=[2(2x−3y)+1][2(2x−3y)−3]
=(4x−6y+1)(4x−6y−3)
Answered by
1
Answer:
hey
Step-by-step explanation:
answer...
Simplify
1
Expand the square
8
(
−
3
)
2
+
4
(
−
3
)
8
(
−
3
)
(
−
3
)
+
4
(
−
3
)
2
Distribute
8
(
−
3
)
(
−
3
)
+
4
(
−
3
)
8
(
(
−
3
)
−
3
(
−
3
)
)
+
4
(
−
3
)
3
Distribute
8
(
(
−
3
)
−
3
(
−
3
)
)
+
4
(
−
3
)
8
(
2
−
3
−
3
(
−
3
)
)
+
4
(
−
3
)
4
Distribute
8
(
2
−
3
−
3
(
−
3
)
)
+
4
(
−
3
)
8
(
2
−
3
−
3
+
9
2
)
+
4
(
−
3
)
5
Combine like terms
8
(
2
−
3
−
3
+
9
2
)
+
4
(
−
3
)
8
(
2
−
6
+
9
2
)
+
4
(
−
3
)
6
Distribute
8
(
2
−
6
+
9
2
)
+
4
(
−
3
)
8
2
−
4
8
+
7
2
2
+
4
(
−
3
)
7
Distribute
8
2
−
4
8
+
7
2
2
+
4
(
−
3
)
8
2
−
4
8
+
7
2
2
+
4
−
1
2
Solution
8
2
−
4
8
+
7
2
2
+
4
−
1
2
❣❣❣❣❣❣❣❣❣❣❣
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