Question

factorise 8 x cube + 729 + 108 X square + 486 x​

Answer 1

i hope this helps you

Answer 2

The factors are (2x+9), (2x+9), and (2x+9) or $(2x+9)^3$

Step-by-step explanation:

To factorize: $8x^3 + 729 + 108 x^2 + 486 x$

If we carefully observe the given question, we will find that the first term, $8x^3$ is the cube of 2x.

Also, 729 is the cube of 9.

The term$108x^2$ is$3 \times (2x)^2\times 9$ and the term 486x is$3 \times 2x\times (9)^2$.

Thus, we can apply the formula $(a+b)^3 = a^3 + b^3 +3a^2b + 3ab^2$

where a = 2x , and b = 9 in the given question

Thus $8x^3 + 729 + 108 x^2 + 486 x$ = $(2x + 9)^3$

The factors are (2x+9), (2x+9), and (2x+9).