Question

Factorise 8 x cube + y cube + 27 Z cube minus 18 x y z

Answer 1

8x³+y³+27z3-18xyz

(2x)³+y³+(3z)³-3*(2x)*y*(3z)

a³+b³+c³ -3abc =a+b

Answer 2

$(2x+y+3z) (4x^2 + y^2 + 9z^2 - 2xy -3yz -6zx)$

Step-by-step explanation:

Given that,

$8x^3 + y^3 + 27z^3 - 18xyz$

using the formula

$a^3 + b^3 + c^3 - 3abc = (a + b + c) (a^2 + b^2 + c^2 - ab - bc - ac)$

The equation would be:

= $(2x)^3 + y^3 + (3z)^3 - 3 × 2x × y × 3z$

= (2x + y + 3z) [(2x)^2 + y^2 + (3z)^2 −2x * y − y * 3z − 3z * 2x ]

= $(2x+y+3z) (4x^2 + y^2 + 9z^2 - 2xy -3yz -6zx)$

Learn more: Factorize

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