Math, asked by Notes2451, 1 year ago

Factorise 80a square-45b square

Answers

Answered by TooFree
22

Algebraic identify used:

a² - b² = (a - b)(a + b)


Factorised 80a² - 45b²:

80a² - 45b² = 5(16a² - 9b²)

                    = 5[ (4a)² - (3b)² ]  

                    = 5(4a - 3b)(4a + 3b)


Answer: 5(4a - 3b)(4a + 3b)


Answered by duragpalsingh
9

\text{\huge{\bold{Hey there!}}}\\\\\text{To factorise:}\\80a^2 - 45b^2\\\text{\underline{Taking 5 common,}}\\=5(16a^2 - 9b^2)\\=5\{(4a)^2 - (3b)^2\}\\Now, \ Using, \\ \boxed{ a^2-b^2 = (a+b)(a-b)}\\=5(4a+3b)(4a-3b)\\\\\text{\huge{\bold{Hope It Helps You!}}}


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