Question

factorise 81- 4x square​

Answer 1

hey mate!!

this is your answer..

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Answer 2

81−4x281-4x2

Rewrite 8181 as 9292.

92−4x292-4x2

Rewrite 4x24x2 as (2x)2(2x)2.

92−(2x)292-(2x)2

Since both terms are perfect squares, factor using the difference of squares formula, a2−b2=(a+b)(a−b)a2-b2=(a+b)(a-b)where a=9a=9 and b=2xb=2x.

(9+2x)(9−(2x))(9+2x)(9-(2x))

Multiply 22 by −1-1.

(9+2x)(9−2x)(9+2x)(9-2x)

81−4x281-4x2
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