Question

factorise 81(x+1)^+90(x+1)(y+2)+25(y+2)^​

Answer 1

Step-by-step explanation:

Consider, 81(x+1)2 + 90(x+1) (y+2)+ 25 (y+2)2 Put a = (x + 1) and b = (y + 2) in the above expression, we get 81(x+1)2 + 90(x+1) (y+2)+ 25 (y+2)2 = 81a2 + 90ab + 25 b2 = (9a)2 + 2 × 9a × 5b + (5b)2 It is in the form of a2 + 2ab + b2 = (a + b)2 Hence (9a)2 + 2 × 9a × 5b + (5b)2 = (9a + 5b)2 = [9(x+1) + 5(y + 2)]2 = [9x + 9 + 5y + 10]2 = [9x + 5y + 19]2

hope this will help you...