factorise : 81a^3b^3-3
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Step-by-step explanation:
3(27a^3b^3-1)
3{(3ab)^3-(1)^3}
3[(3ab-1){(3ab)^2+3ab+(1)^2}]
3{(3ab-1)(9a^2b^2+3ab+1)}
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