Math, asked by arpita2334, 4 months ago

factorise : 81a^3b^3-3​

Answers

Answered by muazmaasghar
0

Step-by-step explanation:

3(27a^3b^3-1)

3{(3ab)^3-(1)^3}

3[(3ab-1){(3ab)^2+3ab+(1)^2}]

3{(3ab-1)(9a^2b^2+3ab+1)}

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