Question

factorise : 81a^3b^3-3​

Answer 1

Step-by-step explanation:

3(27a^3b^3-1)

3{(3ab)^3-(1)^3}

3[(3ab-1){(3ab)^2+3ab+(1)^2}]

3{(3ab-1)(9a^2b^2+3ab+1)}