Math, asked by Anonymous, 4 months ago

factorise:81q^2-16c^2

Answers

Answered by aditya1154

6

$81 {q}^{2} - 16 {c}^{2} \\ = > {(9q)}^{2} - {(4c)}^{2} \\ = >( 9q + 4c)(9q - 4c)$

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