Question

factorise 81x^2-198xy+121y^2​

Answer 1

Solution:-

The given polynomial 81x 2 −198xy+121y 2can be factorized as follows:

$81x2−198xy+121y2 \\ =(9x)2−(2×9x×11y)+(11y)2 \\ =(9x−11y)2</p><p>$

$(a−b)2=a2+b2−2ab) \\ </p><p></p><p></p><p>Hence, 81x2−198xy+121y2 \\ =(9x−11y)2</p><p></p><p>$

Answer 2

Step-by-step explanation:

$81 {x}^{2} - 198xy + 121 {y}^{2} = 0 \\ = > {(9x)}^{2} - 2 \times 9x \times 11y + {(11y)}^{2} = 0 \\ = > {(9x - 11y)}^{2} = 0$