Factorise 81x^4 + 4y^4
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Answer:
81x⁴+4y⁴
= (81x⁴+4y⁴+36x²y²) -36x²y²
=(9x²+2y²) ²-(6xy) ²
using identity a²-b²=(a+b) (a-b)
=(9x²+2y²) ²-(6xy) ²=(9x²+2y²+6xy) (9x²+2y²-6xy)
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