factorise 81x^-72xy+12x
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Answer:
We first factorize each term of the given polynomial 8x
2
−72xy+12x as shown below:
8x
2
=2×2×2×x×x
72xy=2×2×2×3×3×x×y
12x=2×2×3×x
The common factors of 8x
2
,72xy and 12x are 2,2 and x, therefore, the HCF is:
2×2×x=4x
Thus, taking out the HCF, we have:
8x
2
−72xy+12x=4x(2x−18y+3)
Hence, 8x
2
−72xy+12x=4x(2x−18y+3).
Step-by-step explanation:
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