factorise: 8a^3 + 27b^3
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8a³+27b³
Formula= a³+b³ =(a+b)(a²- ab + b²)
(2a)³+(3b)³=(2a+3b){(2a)²- (2a)(3b)+(3b)²}
= (2a+3b){4a²-6ab+9b²} Answer.......
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