Factorise: 8a^3- (b^3/27)
[Here the term in the bracket is a fraction]
Please give me the result
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Answer:
a³-b³=(a-b)(a²+b²+ab)
8a³- (b³/27)
(2a)³-(b/3)³=(2à -b/3)(4a²+b²/9 +2ab/3)
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