Factorise :8a^3 - b^3
(8a to the power of 3 - b to the power of 3)
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Answered by
5
Hey mate!!
8a³ - b³
(2a)³ - (b)³
Using identity ;
x³ - y³ = (x - y)(x² + y² + xy)
Therefore,
(2a - b){(2a)² + b² + 2a × b}
=> (2a - b)(4a² + 2ab + b²)
Thanks for the question!
☺☺☺
8a³ - b³
(2a)³ - (b)³
Using identity ;
x³ - y³ = (x - y)(x² + y² + xy)
Therefore,
(2a - b){(2a)² + b² + 2a × b}
=> (2a - b)(4a² + 2ab + b²)
Thanks for the question!
☺☺☺
MsQueen:
Well, I'm not a teacher. But it would be better if U'll write it into this form.
so is it wrong?
:'(
ok np
which?
if we multiply the answer is it wrong?
Np
ok tnx
by the way if its ur real photo in the pic then u look gorgeous
bye
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2
❤❤Here is your answer ✌ ✌
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