factorise 8a cube +27 b cube
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Solution :
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Given that :
_____________
8a³+27b³
=> (2a)³+(3b)³
As we know that :
a³+b³ = (a+b)(a²-ab+b²)
=> 8a³+27b³ = (2a+3b)[ (2a)²-(2a)(3b)+(3b)² ]
=> 8a³+27b³ = (2a+3b)(4a²-6ab+9b²)
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