Question

factorise 8a cube + √27b cube

Answer 1

8a^3+root27b^3
(2a)^3+(3b)^3
(2a+3b)[((2a)^2+2a*3b+(3b)^2]
(2a+3b)[(4(a)^2+6ab+9b^]

Answer 2

Answer:

Step-by-step explanation:

The given equation is:

$8a^3+\sqrt{27}b^3$

which can be written as:

=$(2a)^3+(3b)^3$

Now, using the identity $a^3+b^3=(a+b)(a^2+ab+b^2)$,we get

=$(2a+3b)((2a)^2+2a(3b)+(3b)^2)$

=$(2a+3b)(4a^2+6ab+9b^2)$

which is the required factorized form of the given equation.