Math, asked by yunjin, 1 year ago

factorise 8a cube + √27b cube

Answers

Answered by amanbhatt
80
8a^3+root27b^3
(2a)^3+(3b)^3
(2a+3b)[((2a)^2+2a*3b+(3b)^2]
(2a+3b)[(4(a)^2+6ab+9b^]
Answered by boffeemadrid
13

Answer:

Step-by-step explanation:

The given equation is:

8a^3+\sqrt{27}b^3

which can be written as:

=(2a)^3+(3b)^3

Now, using the identity a^3+b^3=(a+b)(a^2+ab+b^2),we get

=(2a+3b)((2a)^2+2a(3b)+(3b)^2)

=(2a+3b)(4a^2+6ab+9b^2)

which is the required factorized form of the given equation.

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