Question

Factorise 8a2-
$8xa {?}^{2} { - 16ab}$
16ab​

Answer 1

The factors are 8a and (a-2b).

• The product of a polynomial's factors with degrees that are less than or equal to the original polynomial can be used to represent a polynomial. Factorization of polynomials is the technical term for the factoring process. The process of factoring a number into positive prime factors is a common one. A prime number is one with only 1 and itself as its positive components. Prime numbers include, for example, 2, 3,5, and 7.
• Grouping is an approach to factoring. When there are factors that are common to some of the terms in a polynomial but not all of the terms, this method is utilised. Two words with a minus sign between them and perfect squares in both of them are required by the definition of a difference in two perfect squares. After factoring the difference between two perfect squares, the outcome should have two binomial terms. One of the two words in a binomial term carries their total, whereas the other term contains their difference.

Here, according to the given information, we are given that,

$8a^{2} -16ab\\=8a(a-2b)$

Hence, the factors are 8a and (a-2b).

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